an angle of radius 20cm subtends an angle of 90 degree at the center . find the area of the corresponding major segment of the circle
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Step-by-step explanation: r=20cm ∠POQ=90°
∴ the triangle is an right angled isosceles Δ
first, area of minor segment = area of minor sectorPOQ - area of ΔPOQ
= ∅/360 *πr² - 1/*b*h
= 90/360 *22/7*20*20
= 1100/7 cm²
area of major segment = area of circle - area or minor segment
= πr² - 1100/7 cm²
= 22/7*20*20 - 1100/7
= 8800/7 - 1100/7
= 7700/7 = 1100cm²
hope this is correct , good day:)
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