Question

An ant covers 2cm , 1.5cm ,2,5cm, 3cm
and 1 cm in one second each. The average
speed of the ant is.
( a)ms-1
(b) 2.5ms-1
(C) 1.5ms-1
(d) none of the above​

Answer 1

Answer:

• Average speed of ant = 2.25 cm/s

Explanation:

Given:

• Ant covers 2 cm, 1.5 cm, 2.5 cm and 3 cm distance.
• Time = 1 sec for each.

To Find:

• Average speed of ant.

Now,

=> Total Distance = 2 + 1.5 + 2.5 + 3 cm

=> Total Distance = 9 cm

Now,

=> Total Time = 1 + 1 + 1 + 1 sec

=> Total Time = 4 sec

Now, we know that,

=> Average Speed = Total Distance/Total Time

=> Average speed = 9/4

=> Average speed = 2.25 cm/s

Hence, Average speed of Ant is 2.25 cm/s.

Answer 2

Given:

Distance travelled by an ant in:

➺ First sec= 2cm

➺ Second sec= 1.5cm

➺ Third sec= 2.5cm

➺ Fourth sec= 3cm

To Find:

Average speed of ant

Solution:

We know that,

$\bf{Average\:Speed\:of\:Body=\dfrac{Total\:Distance\:Covered}{Total\:Time\:Taken}}$

Now,

$\sf{Total\:Distance\:covered\:by\:ant=2+1.5+2.5+3=9cm}$

So,

$\rightarrow\sf{Average\:Speed\:of\:Ant=\dfrac{9}{4}\:cm/s=2.25\:cm/s}$

$\rightarrow\sf{Average\:Speed\:of\:Ant=\dfrac{9}{4\times100}\:m/s=0.0225\:m/s}$

Hence, the average speed of ant during given journey is 0.0225 ms⁻¹.