Question

An ant covers 60cm displacement of a circular path of 60 cm the total distance travelled by ant is​

Answer 1

Answer:

Let us move the mirror to the point Q. Ant is covering a distance of PQ(=60cm) in 2×60s. ∠PQM=30

0

.

From similar triangle we get, ∠MQ

1

P

1

=30

0

Since ∠PQP

1

=60

0

, we get PQ=P

1

Q

1

=PP

1

=60cm

Now, PP

1

=60cm and QQ

1

=0cm.

So, the rate at which the distance between ant and its image change is

2×60

60

cm/s=0.5cm/s

Answer 2

Answer:

ant cover= 60cm

circle path of 60cm

similarly,

60+60=180

120=180

120-180

60/120

=2