Question

An ant is at one of the corners of cube with sides 10.m what is the mininum distance in meter that the ant has to crawl to reach the farthest corner on the cube

Answer 1

# Answer = 22.36 m

# Explanation-

Look at figure for reference.

Consider a cube with side length s.

If an ant is at point A, farthest point from A will be C.

Observing from the figure,

It would have to crawl from A to B to C.

From second figure we'll know that

Using Pythagorean theorem,

AC^2 = AD^2 + CD^2

AC^2 = s^2 + (2s)^2

AC^2 = 5s^2

AC = √5s

AC = 10×√5

AC = 22.36 m

Ant will have to crawl for 22.36 m to reach farthest point.

Answer 2

Answer:

10+(1+√2)

Step-by-step explanation:

According to me,

10+10√2

= 10+(1+√2)