Question

An AP arithmetic progression is given that is 2,3,4,6,8,9,10 and find the sum of their n terms in an AP

Answer 1

Answer:

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Step-by-step explanation:

$sum \: = \frac{n}{2} (2a + (n - 1)d) \\ \\ a = 2 \\ d = 3 - 2 = 1 \\ \\ sum \: of \: nth \: term = \frac{n}{2}(2(2) + (n - 1)1) \\ = \frac{n}{2}(4 + n - 1) \\ \\ = \frac{n}{2} (3 + n) \\ \\ = \frac{3n + {n}^{2} }{2}$

Answer 2

Answer:

Step-by-step explanation:

we know that Sn = n/2(a+l) (where Sn, a, n and l have their usual meanings)

here given that a = 2 and d = 3-2 = 1

==>Sn=n/2(2+10)

==>Sn=n/2(12)

==>Sn=6n

==>sum of their n terms is 6n

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