Question

The distance of the chord with length r from the center of the circle having radius r is ........
(A) √3/2r
(B) √3r
(C) 2r
(D) r/r

Answer 1

Answer:

2r

Explanation:

chord is bisected by the radius

Answer 2

Answer: option a

Explanation:

According to pythagoras-theorem

Chord square + base square = radius square(here.)

So

r^2=chord^2+(r/2)^2

Chord^2=r^2-(r^2/4)

Taking LCM

Chord^2 =3r^2/4

Chord=Square root of 3 *r/2