Question

An AP consint of 31 terms if it's 16 term is m then sum of all the term

Answer 1

Answer:

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Step-by-step explanation:

Here,

a16=p

=>a+15d=p

=>a=p-15d

Let all terms be '31' in this AP

Therefore,

Sn=31/2[(2a+(n-1)]

Sn=31/2[2(p-15d)+(31-1)d]

Sn=31/2[2p-30d+30d]

Sn=31/2 x 2p

Sn=31

Answer 2

Given:

number of terms (n) = 31

a+15 d= m -------(1)

formula for sum of terms

${sn=\frac{n}{2}(a+(n-1)d)}$

${sn=\frac{31}{2}((m-15d)+(31-1)d)}$

${sn =31}$

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