Question

An AP consist of 50 terms of which 3rd term is 12 and the last term is 106 .Find the 29th term.

Answer 1

a+11d=106
a+49d=106
subtracying 2 from 1
a-a-2d+49d=-12+106
47d=94
d =2
putting the value
a=12
29th term
a+n-1*d
12+28×2
68 anser

Answer 2

hey mate!

here is your answer:

according to the question
a+(3-1)d=12......(1)
and a+(50-1)d=106......(2)
a+2d=12
and a+49d=106
now, a=12-2d
putting the value of a in (2) equation
i.e 12-2d+49d=106
12+47d=106
47d=106-12
47d=94
d=94/47
d=2

a=12-2d
a=12-4
a=8

now, 29th term =a+28d
=8+28(2)=8+56=64

hope it helped!