Question

an ap consist of 5q terms of which 3rd term is 12 and the last term is 106 , find the 29th term ?

Answer 1

=)a50 = a + 49d = 106 .....(1)

a3 = a + 2d = 12......(2)

Now, subtract equation .(1) - (2)
=) d = 2

Therfore substituing value in eq(2)

a + 2 ×2 = 12
a = 8 
Now...nth term....an = a + (n - 1)d

an = 8 + (29 - 1) 2 = 64

So, 29th term=64.

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