Question

An AP consist of 60 terms if the first and the last term be 7 and 115 respectively find 32nd term

Answer 1

Answer:

Given,n = 60, a1 = 7,

and a60 = 115  

⇒ a1 + 59d = 115

7 + 59d = 115

59d = 108  

d = 108/59

a32 = a1 + 31d = 7 + 31(108/59) = 7 + 3348/59

∴ a32 = (59*7)/59 + 3348/59

a32= (413+3348)/59

a32=3761/59

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