an ap consists of 37 terms . the sum of three middle most term is 225 and the sum of last three is 429 find the ap
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The middle term (19th term) is 75, and the 36th term is 429/3 = 143. The 17 steps from t19 to t36 added 143-75 = 68, so each step adds 68/17 = 4.
Hence the first term is 75-72 = 3. The terms of the ap are:
3,7,11,15,19,23,
27,31,35,39,43,47,
51,55,59,63,67,71,
75,79,83,87,91,95,
99,103,107,111,115,
119,123,127,131,135,
139,143,147.
t_n = 4n - 1.
Hence the first term is 75-72 = 3. The terms of the ap are:
3,7,11,15,19,23,
27,31,35,39,43,47,
51,55,59,63,67,71,
75,79,83,87,91,95,
99,103,107,111,115,
119,123,127,131,135,
139,143,147.
t_n = 4n - 1.
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