Question

an ap consists of 50 terms of which 3 term is 12 and the last term is 106 find the 29th term​

Answer 1

Answer:

64

Step-by-step explanation:

N=50

A+2D=12        (1)

A+49D=106    (2)

47D=94

D=2

A+28D=8+56

ANS:64

Answer 2

Answer:

$\huge{\red{\boxed{\boxed{\green{\sf{a29=64}}}}}}$

Step-by-step explanation:

$\huge{\red{\boxed{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}}$

□a3=12

□a50=106

□n=50

To find:

○29th term:?

$a3 = 12 \\ a + 2d = 12 - - - - - (1) \\ again \\ a50 = 106 \\ a + 49d = 106 - - - - - (2) \\ \\subtract \: (1) \: from \: (2) \\ = )a + 49d - (a + 2d) = 106 - 12 \\ = )a + 49d - a - 2d = 94 \\ = )47d = 94 \\ = )d = \frac{94}{47} \\ = )d = 2 \\ \\ putting \: value \: of \: d \: in \: (1) \\ = ) a + 2d = 12 \\ = )a + 2 \times 2 = 12 \\ = )a + 4 = 12 \\ = )a = 12 - 4 \\ = )a = 8 \\ \\again \\ a29 = a + 28d \\ = )8 + 28 \times 2 \\ = )8 + 56 \\ = )64$

$\huge{\red{\boxed{\boxed{\green{\sf{a29=64}}}}}}$