An AP consists of 50 terms of which 3rd term is 12 and the last term is 106.Find the 29th term
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Answered by
23
n = 50
a3 = 12 and a50 = 106 so
a+2d = 12 and a+49d = 106
subtract it
a+2d -(a+49d) = 12- 106
- 47d =-94
d = 2
a+2(2) = 12
a+4 = 12
a = 8
a29 = a + 28d
8 + 29(2) = 66
therefore a29 = 66
a3 = 12 and a50 = 106 so
a+2d = 12 and a+49d = 106
subtract it
a+2d -(a+49d) = 12- 106
- 47d =-94
d = 2
a+2(2) = 12
a+4 = 12
a = 8
a29 = a + 28d
8 + 29(2) = 66
therefore a29 = 66
Kushal456:
Your answer is wrong
yea its 64
any way u understood process right
i made the mistake there k
a + 28d = a29
8 + 28(2)
8 +56 = 64 so, it is 64
sry for the mistake
Hmm
u can correct there itself
Answered by
9
This is your answer hope it will help u
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chill..
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