Question

An AP consists of 50 terms of which 3rd term is 12 and the last term is 106 find the 25 term​

Answer 1

QUESTION Correct option is

Correct option isA

Correct option isA64

Correct option isA64a+2d=12

Correct option isA64a+2d=12a+49d=106

Correct option isA64a+2d=12a+49d=106⇒47d=94

Correct option isA64a+2d=12a+49d=106⇒47d=94⇒d=2

Correct option isA64a+2d=12a+49d=106⇒47d=94⇒d=2a+4=12

Correct option isA64a+2d=12a+49d=106⇒47d=94⇒d=2a+4=12⇒a=8

Correct option isA64a+2d=12a+49d=106⇒47d=94⇒d=2a+4=12⇒a=829th term : - 

Correct option isA64a+2d=12a+49d=106⇒47d=94⇒d=2a+4=12⇒a=829th term : - a+28d=8+56=64

Answer 2

Explanation:

GIVEN

• 3rd term = 12
• last term = 106
• Number of Total Term = 50

SOLUTION

• a + 2d = 12 → (i)
• a + 49d = 106 → (ii)

Solving above Equation, we get

• 47d = 94
• d = 2

• a + 4 = 12
• a = 8

NOW

• 25th term

= a + 24d

= 8 + 48

= 56