Question

An ap consists of 50 terms of which 3rd terms is 12 and the last term is 106. Find the 29 th term

Answer 1

n=50
According to question

L = 106
a + (50-1)d= 106
a+ 49d = 106 -----------------(1)

T3 = a + (3-1)d
12 = a+ 2d
a+2d = 12 ---------------(2)


Subtracting equation 2 from 1,we get

47d = 94
d = 2

Putting the value of d in equation 2, we get
a+2*2 = 12
a = 12-4
a=8

T29 = a+28d
T29 = 8 + 28 *2
T29 = 8 + 56
T29 = 64


Hope it help you



Please mark as brainliest if you liked the solution

Answer 2

this is aright answer....