An AP consists of 50th terms of which 3rd term is 12 & last term is 106. find the 29th term
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n=50
3rd term = 12
50th term =56
3rd term=a+2d=12 .......1)
50th term=a+49d=106.......2)
Subtract 2) from 1)
a+49d=106
a+2d =12
________
- - -
________
47d=94
d=2
a+2d=12
a+2(2)=12
a+4=12
a=8
29th term = a +28d
= 8+28(2)
= 8+56
= 64
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3rd term = 12
50th term =56
3rd term=a+2d=12 .......1)
50th term=a+49d=106.......2)
Subtract 2) from 1)
a+49d=106
a+2d =12
________
- - -
________
47d=94
d=2
a+2d=12
a+2(2)=12
a+4=12
a=8
29th term = a +28d
= 8+28(2)
= 8+56
= 64
DETAILED ANSWER
PLEASE MARK IT AS BRAINLIEST
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