ax + by + c = 0 does not represent an equation of line when ...........
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Answer:
Step-by-step explanation:
In that case, you'll either have either
* c = 0, in which case the equation is satisfied by the whole cartesian plane.
* c != 0, in which case the equation is not satisfied by any point on the cartesian plane.
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Quora User
Anonymous
Answered Dec 21, 2013
If you allow a, b and c to take imaginary values then it represents a point lying on the intersection of two lines in the following way-:
let a=s+it and b=u+iv and c=g+ih, then equation ax+by+c=0 reduces to
sx+uy+g+i(tx+vy+h)=0 -(2)
which is a point lying on the intersection of two lines given by the real and imaginary part of the equation (2).
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Robert J. Kolker
Robert J. Kolker
Answered Dec 21, 2013 · Author has 23.3k answers and 16.6m answer views
b = c = 0
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