An ap consists of thirty seven terms the sum of middle most terms are to twenty five and the sum of last three terms is four twenty nine find the ap
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Que. An A.P. Consist of 37 Terms. The Sum of Three middle most term is 225 and the sum of the last three term is 429. Find the A.P.
Solution:-
Given:-
☆ A.P. Consist of 37 Terms.
☆ Sum of Three Middle Most Term = 225.
☆ Sum of Last three terms = 429.
Now,
Middle Term for an ODD A.P = (37 + 1)/2
=> Middle most Term = 19.
Hence,
Three Middle Most Term = 18, 19 & 20.
A.T.Q.
(a + 17d) + (a+18d) + (a + 19d) = 225
=> 3a + 54d = 225
=> a + 18d = 75
=> a = 75 - 18d______________(1).
Sum of Last Three Term,
=> ( a +37d ) + ( a+36d) + (a+35d) = 429
=> 3a + 108d = 429
=> a + 36d = 143__________(2)
Putting eq(1) in eq(2). we get,
=> 75 - 18d + 36d = 143
=> 17d = 143 - 75
=> d = 68/17
=> d = 4
Now,
Substituting d=4 in eq(1).
=> a = 75 - 18×4
=> a = 75 - 72
=> a = 3.
Hence,
The A.P. is 3, 7, 11, 15,.........
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