An AP contains of 37 terms the sum of three middle most terms is 225 and the sum of the last three is 429. Find the value of AP
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three middle most terms= a+17 a+18 a+19
a+17d+a+18d+a+19d=225
3a+54d=225
a+18d=75 -(1)
Now,
a+34d+a+35d+a+36d=429
3a+105d=429
a+35d=143 -(2)
by eq. (1) &(2)
a+18d=75
a+35d=143
_ _ _
-17d = -68
Therefore,
d=4
and ,
a=75-72
=3
ANSWER.
a+17d+a+18d+a+19d=225
3a+54d=225
a+18d=75 -(1)
Now,
a+34d+a+35d+a+36d=429
3a+105d=429
a+35d=143 -(2)
by eq. (1) &(2)
a+18d=75
a+35d=143
_ _ _
-17d = -68
Therefore,
d=4
and ,
a=75-72
=3
ANSWER.
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