An AP has first term as 5 and common difference as 3 if the last term is 50 find the number of terms and also find the sum of terms
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Answered by
2
Step-by-step explanation:
here
a=5
d=3
l=50
50=a+(n-1)d
=5+3n-3
=2+3n
thus 3n=48
n=16
total number of terms in ap is 16
Sum of terms of ap
=(n(a+l))/2
=(16(5+50))/2
=8(55)
=440
Answered by
0
Answer:
Step-by-step explanation:
First term (a) =5
Common difference (d) = 3
Last term (An) = 50
An = [a+(n-1)d]
50 =5+(n-1) X 3
50-5=3n-3
45+3=3n
48/3=n
16= n
A16 = 50
Sum of A.P:
Sn=n/2[2a+(n-1)d]
Sn=16/2[2X5+(16-1)X3]
Sn=8(10+45)
Sn=55X8
Sn=440
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