An apple falls freely from a tree. (i) What is its velocity after 5 ? (ii) What is the distance covered
by it in 5 ?
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Answer:
v= u±at
u, Initial velocity of apple=0
a, acceleration due to gravity=10 m/s²
t, time = 1.5 second
v, speed of apple=?
v=0±10×1.5=15
>Speed after 1.5 sec =15m/s
Distance covered by apple:-
s=ut±1/2at²
u=0; t=1.5sec ;a=10m/s²
s=0×1.5±1/2×10×(1.5)²=0±1/2 ×10×2.25=11.25
Distance covered by the apple=11.25m
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