An apple of mass 0.1 kg is dropped from a height 1m. Find out the value of the kinetic energy when it hits the ground.
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Given : An apple of mass 0.1 kg is dropped from a height 1m.
To Find : the value of the kinetic energy when it hits the ground.
Solution:
TE = KE + PE
TE = Total energy
KE = Kinetic Energy = (1/2)mv²
PE= Potential Energy = mgh
An apple of mass 0.1 kg is dropped from a height 1 m.
m = 0.1 kg
h = 1 m
g = 10 m/s²
v = 0
At height 1 m
TE = 0.1 (10) (1) + (1/2)(0.1) (0)²
=> TE = 1 + 0 = 1 joule
At ground when hits :
m = 0.1 kg
h = 0 m
g = 10 m/s²
TE = 0.1 (10) (0) + KE
=> TE = 0 + KE
=> KE = TE
=> KE = 1 joule
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