an appliance of resistance 22 ohms is connected across a 'v' of 220 v. find the amount of charge flowing in 10 mins
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Resistance,R = 22ohms.
Potential difference,V = 220V
Time = 10 minutes = 600s.
By ohms law, we have
V = IR
I = V/R
I= 220/22.........(V = 220V & R=22)
I = 10A
Hence, current is 10 ampere
Now, We know that I = Q/t..........(Q= charges
moved &
t= time
taken)
Q= I*t
Q= 10*600
Q= 6000C
Hence, Charges moved is 6000C
Potential difference,V = 220V
Time = 10 minutes = 600s.
By ohms law, we have
V = IR
I = V/R
I= 220/22.........(V = 220V & R=22)
I = 10A
Hence, current is 10 ampere
Now, We know that I = Q/t..........(Q= charges
moved &
t= time
taken)
Q= I*t
Q= 10*600
Q= 6000C
Hence, Charges moved is 6000C
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