Question

An aqueous solution 44.8 volume H2O2 solution having density = 1.036 g/ ml .Calculate Molalility morality, % w/ v , w/w and mole fraction. ​

Answer 1

Answer:

Calculate Molalility morality, % w/ v , w/w and mole fraction. ... An aqueous solution 44.8 volume H2O2 solution having density = 1.036 g/ ml .

Answer 2

The molality, morality, % w/ v , w/w and mole fraction are 812.5 m, 30 M, 103%, 96% and 0.94 respectively.

Given,

Volume of H2O2 solution=44.8 mL

Density of the solution=1.036 g/mL.

To find,

the molality, morality, % w/ v , w/w and mole fraction. ​

Solution:

The volume of the solution can be found from the following expression:

$Density=\frac{Mass}{Volume}$

The mass of the solution will be:

$Density=\frac{Mass}{Volume} \\Volume=\frac{Mass}{Density} \\Volume=\frac{44.8}{1.036} \\Volume=43.2 mL.$

Mass of solution=Mass of solvent+Mass of solute

The mass of the water(solvent) in the solution will be:

Mass of solution=Mass of solvent+Mass of solute

Mass of solvent=Mass of solution-Mass of solute

Mass of solvent=(46.4-44.8)g

Mass of solvent=1.6 g.

The molality of the solution can be found from the following expression:

$Molality=\frac{Moles}{Mass of solvent(Kg)}$

The moles of the H2O2(solute) will be:

$Moles=\frac{Mass}{Molar mass} \\Moles=\frac{44.8}{34} \\Moles=1.3.$

The molality of the solution will be:

$Molality=\frac{Moles}{Mass of solvent(Kg)}\\Molality=\frac{1.3}{\frac{1.6}{1000} } \\Molality=812.5 moles/Kg.$

The molarity of the solution can be found from the following expression:

$Molarity=\frac{Moles}{Volume(L)}$

The molarity of the solution will be:

$Molality=\frac{Moles}{Volume(L)}\\Molality=\frac{1.3}{\frac{43.2}{1000} } \\Molality=30 moles/L.$

The %w/v of the solution can be found from the following expression:

%w/v=Mass of solute/Volume of solution(mL) x 100

The %w/v of the solution will be:

%w/v=Mass of solute/Volume of solution(mL) x 100

$w/v=\frac{44.8}{43.2} X 100\\w/v=103 percent.$

The %w/w of the solution can be found from the following expression:

%w/v=Mass of solute/Mass of solution x 100

$w/w=\frac{44.8}{46.4} X 100\\w/v=96 percent.$

The mole fraction of the solution can be found from the following expression:

$Xa=\frac{na}{na+nb}$

The mole fraction of the solution will be:

$Xa=\frac{na}{na+nb}\\Xa=\frac{1.3 }{1.3+\frac{1.6}{18} } \\Xa=\frac{1.3}{1.3+0.08} \\Xa=\frac{1.3}{1.38} \\Xa=0.94.$

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