Chemistry, asked by Aanyashukla8817, 1 year ago

An aqueous solution has a mass of 490 grams containing 8.5×10-3 gram of calcium ions. What is the concentration of calcium ions in this solution?

Answers

Answered by divyaratns
0

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Answered by CarlynBronk
3

The question is incomplete, here is the complete question:

An aqueous solution has a mass of 490 grams containing 8.5 × 10⁻³ gram of calcium ions. The concentration of calcium ions in this solution is

1. 4.3 ppm

2. 8.5 ppm

3. 17 ppm

4. 34 ppm

The concentration of calcium ions in the solution is 17 ppm

Explanation:

ppm is the amount of solute (in milligrams) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of calcium ions in solution, we use the equation:

\text{ppm}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6

Both the masses are in grams.

We are given:

Mass of calcium ions = 8.5\times 10^{-3}g

Mass of solution = 490 g

Putting values in above equation, we get:

\text{ppm of calcium ions in solution}=\frac{8.5\times 10^{-3}}{490}\times 10^6\\\\\text{ppm of calcium ions in solution}=17ppm

Learn more about ppm:

https://brainly.in/question/1065094

https://brainly.in/question/7533552

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