Question

An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 ml .The volume of 0.1n naoh required to neutralise 10 ml of solution os

Answer 1

Explanation:

Sol. Oxalic acid dehydrate H2C2O4 . 2H2O : mw = 126 It is a dibasic acid, hence equivalent weight = 63 ⇒ Normality = 6.3/63 × 1000/250 = 0.4 N ⇒ N1V1 = N2V2 0.1 ×V1 = 0.4 × 10 Hence, V1 = 40 mL.