An aqueous solution of Ca(NO3)2 has the molality of 0.75 mol.kg-¹. If 75% Ca(NO3)2 dissociates in solution, what will be the boiling point of solution? Giver kb=0.52k.kg.mol-¹
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Answer:
The molar mass calcium nitrate is 164 g/mol. 7 g of calcium nitrate
164
7
=0.0427 moles.
The molar mass of water is 18 g/mol. 100 g of water =
18
100
=5.56 moles
The mole fraction of calcium nitrate =X=
0.0427+5.56
0.0427
=0.00762
The degree of dissociation α=70 % =0.7
The van't Hoff factor i=[1+(n
′
−1)α]
i=[1+(3−1)×0.7]
i=2.4
The relative lowering of the vapour pressure
P
o
P
o
−P
=iX
760
760−P
=2.4×0.00762=0.018
760−P=13.9
P=746.10mm
Explanation:
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