an aqueous solution of glucose Contain 1 mole of glucose in 1.8 l litre solution thus
Answers
Answered by
1
Answer:
10 g glucose is present in 100 mL solution.
Moles of glucose =
180
10
=
18
1
Molarity=
Volume(Litres)
Molesofsolute
=
18×0.1
1
=
9
5
M
Let the volume required for 1 mole glucose solution be V
⟹
9
5
×V=1
⟹V=
5
9
Litres=1.8 Litres
Explanation:
Similar questions