Chemistry, asked by rohitrohitrohit96101, 6 months ago

an aqueous solution of glucose Contain 1 mole of glucose in 1.8 l litre solution thus​

Answers

Answered by BrettRivera
1

Answer:

10 g glucose is present in 100 mL solution.

Moles of glucose =

180

10

=

18

1

Molarity=

Volume(Litres)

Molesofsolute

=

18×0.1

1

=

9

5

M

Let the volume required for 1 mole glucose solution be V

9

5

×V=1

⟹V=

5

9

Litres=1.8 Litres

Explanation:

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