An aques solution of urea is in which 680 gram of urea is disslove in 3200 gram of water if the density of solution is 1.5g/ml than calculate... (1) mass percent by mass (2) mass percent by volume...<br />do this question fast......<br />step by step....
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here mass % = 680/3880×100 = 17.5 % mass / volume% =. 17.5 / volume here volume=. m/ d 3880 / 1.5 = 2586.6. hence 17.5 × 100 / 2586.6=. 0.67
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