Question

An arch way is in the shape of a semi ellipse the road level being the major axis of the breadth of the arc is 30 feet and a man 6 feet tall just touches the top when 2 feet from the side, find the greatest height of the arch

Answer 1

Step-by-step explanation:

Given An arch way is in the shape of a semi ellipse the road level being the major axis of the breadth of the arc is 30 feet and a man 6 feet tall just touches the top when 2 feet from the side, find the greatest height of the arch

• Now we have a coordinate axis and there is an ellipse.
• So distance of arc (semi major axis) is 30 ft
• Now we have ellipse = x^2 / a^2 + y^2 / b^2 = 1
• So a = 30 ft
• Given 2 ft from the side so it will be 30 – 2 = 28
• So when x = 28, y = 6
• So substituting we get
•             So x^2 / 30^2 + y^2 / b^2 = 1
•             So 28^2 / 30^2 + 6^2 / b^^2 = 1
•               So 36 / b^2 = 1 – 28^2 / 30^2
•               So b^2 = 36 x 30^2 / 30^2 – 28^2
•             So b^2 = 32400 / 116
•             So b^2 = 279.3
•              Or b = 16.71

So greatest height will be a minr axis = 16.71 ft

Reference link will be

https://brainly.in/question/1842214

Answer 2

Answer:

B=16.71ft hope it helps you