An archer shoots an arrow with an initial velocity of 21m/s straight up from his bow. He quickly reloads and shoots another arrow in the same way 3.0s later. At what time and height do the arrows meet?[please tell the way also]
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The arrow initial velocity=21m/s
After reaching a particular height it will have a final velocity=0
It will again acquired certain speed when moving down
n it is mentioned that the second arrow was shot with the same way
which means they will have same initial velocity and final velocity
N it will acquire the same speed as the first arrow while moving down
So there is no chance that the two arrows will meet in the air
The will surely meet on the ground which is 0m above the ground
The only possibility that the arrow will meet in the air is if the arrow is shot 3 times faster than the first one
So if shot three times faster they will meet at 63m
After reaching a particular height it will have a final velocity=0
It will again acquired certain speed when moving down
n it is mentioned that the second arrow was shot with the same way
which means they will have same initial velocity and final velocity
N it will acquire the same speed as the first arrow while moving down
So there is no chance that the two arrows will meet in the air
The will surely meet on the ground which is 0m above the ground
The only possibility that the arrow will meet in the air is if the arrow is shot 3 times faster than the first one
So if shot three times faster they will meet at 63m
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