Question

An architect makes a model of a new house. The model shows a tile patio in the backyard. In the​ model, each tile has length one third in.
and width one-sixth in.
The actual tiles have length one-half ft
and width one fourth ft
. What is the ratio of the length of a tile in the model to the length of an actual​ tile? What is the ratio of the area of a tile in the model to the area of an actual​ tile?

Answer 1

Answer:

1/324

Step-by-step explanation:

Since, Here Each tile has length one third in and width one sixth in.

That is L_1 = 1/3 inches and W_1 = 1/6 inches

And, the actual tiles have length one half ft and width one fouth ft.

That is L_2 = 6 inches and W_2 = 3 inches ( because 1 foot = 12 inches)

Thus the ratio of length of the actual length of tile =

$\frac{L_1}{L_2}= \frac{1/3}{6}= \frac{1}{18}$

And, The ratio of tile in the model of the actual area = Area of the tile in model/ actual area

=$\frac{1/3\times 1/6}{6\times 3}$

= 1/324