Question

An Area 0.25 m^2 is held parallel to Y-Z plane in an electric field given E=(4j^+3k^) N/C. Calculate the electric flux linked with it in each case.​

Answer 1

Answer:

zero

Explanation:

electric flux = E.dS

here, the area is held parallel to yz plane which means that it's area vector will be in x direction.

and as you see there is no component of electric field in x direction.(from 0i^+4j^+3k^)

therefore, flux =E×dS

=0×0.25

=0

hope this helps...!