An arithmatic progression has
its 5th term 30 and 9 term
54 find the series
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Answer:
Question:-
An Arithmetic progression has its 5th term 30 and 9th term 54;find the sequence of A.P.
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Required Answer:-
Given:- t5=30
t9=54
To find:- sequence of A.P.
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Solution:-
1) t5=30-(given)
tn=a+(n-1)d
t5=a+(5-1)d
30=a+4d
a+4d=30-(i)
2) t9=54-(given)
tn=a+(n-1)d
t9=a+(9-1)d
54=a+8d
a+8d=54-(ii)
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3) subtracting equation (i) and (ii)
a+4d=30 -(i)
-a-8d= -54 -(ii)
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-4d= -24
4d= 24
d=24/4
d=6
4) put d=6 in equation (i)
a+4d=30
a+4(6)=30
a+24=30
a=30-24
a=6
5) First term of an A.P. is a=6
6) Common difference(d)=6
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7) Now, to find the sequence of
A.P., find next terms by using formula:-
t2= t1+d
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8) t2=t1+d
t2=6+6 -(from 4 and 3)
t2=12
9) t3=t2+d
t3=12+6-(from 8 and 4)
t3=18
10) t4=t3+d
t4=18+6 -(from 9 and 4)
t4=24
11) Therefore, Sequence of an A.P. is 6,12,18,24.......
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Hope it help you.
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