Question

An arithmetic sequence starts 5,9,13,... What is its next term ? is 2012 a term of this sequence?why?

Answer 1

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Answer 2

given arithmetic progression is 5, 9, 13..... here a= 5, d =4..
Nth term of this arithmetic progression is 2012..
.
.
therefore,
[(for forward process see the image given above)]
$n = \frac{2011}{4} \: \: is \: not \: an \: integer$
therefore 2012 is not the term in sequence of arithmetic progression 5, 9, 13....