An army contingent of 404 members is to march behind an army band of 96 members in a
parade. The two groups are to march in the same number of columns . what is the
maximum number of columns in which they should march ?
Answers
Answered by
2
Answer:
See carefully and if it helps you , you must like the ans
sol.... Total n. of members=404
total n. in each band=96
so, the maximum n.of columns in which they should march is = the (hcf of 404 and 96)
Hcf of 404 and 96 = 4
so, Required n.of columns =4 ans.....
Please mark me as Brainliest
Answered by
0
Answer:
It is the correct answer.
Step-by-step explanation:
Hope this attachment helps you.
Attachments:
Similar questions