Question

An army contingent of 616 members is to march behind an army band of 32 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?

Answer 1

SOLUTION :

We have to find the HCF of 616 and 32, to find the maximum number of column in which the groups can march.

Given :  

Number of members in an army = 616

Number of members in band = 32.

Here, 616  > 32

Let a = 616 and b = 32

616 = 32 x 19 + 8

[By applying division lemma, a = bq + r]

Here, remainder = 8 ≠ 0, so take new dividend as 32 and new divisor as 8.

Let a = 32 and b= 8

32 = 8 x 4 + 0.

Here, remainder is zero and divisor is 8

So ,H.C.F. of 616 and 32 is 8.

Hence, maximum number of columns is 8,in which they can march.

HOPE THIS ANSWER WILL HELP YOU….  

Answer 2

To find answer to these questions , simply find HCF.

Check attachment

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