An aromatic compound "a" on treatment with aqueous ammonia and heating forms compound "b" which on heating with br2 and koh forms compound "c" of molecular formula c6h7n. Which one of then correctly identifies compounds "a", "b" and "c"
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Answered by
13
Answer:
We know, the formula of aniline is C6H5NH2.
=> c-Aniline
Therefore, the conversion of b to c is Hofmann debromamide rxn.
=>b-Benzamide (C6H5CONH2)
Assuming tht a was treated with aq.NH3 and Heated to give b,
=>a-Benzoic Acid (C6H5COOH)
Answered by
1
Answer:
We know, the formula of aniline is C6H5NH2.
=> c-Aniline
Therefore, the conversion of b to c is Hofmann debromamide rxn.
=>b-Benzamide (C6H5CONH2)
Assuming tht a was treated with aq.NH3 and Heated to give b,
=>a-Benzoic Acid (C6H5COOH)
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