an arrow is launched straight up with a velocity of 12.6 m/s. how long before arrow returns to the ground
Answers
Apply 1st equation of motion
Concept:
The acceleration that objects experience due to the combined action of gravity and centrifugal force is known as the Earth's gravity, and it is represented by the Greek letter g.
Given:
The velocity of the arrow launched straight up from the ground is 12.6 m/s.
Find:
The time taken by the arrow to return the group.
Solution:
The velocity of the arrow is u = 12.6 m/s .
The final velocity of the arrow when it reached the top is v = 0 m/s.
Since the arrow is fired against gravity.
Therefore, g = -9.8 m/s²
Using the formula :
v = u + gt
0 = 12.6 + (-9.8)t
12.6 = 9.8(t)
t = 1.26 s
To reach the ground from the topmost point, the arrow will take the same time.
Therefore, the total time taken by the arrow to reach the ground after being launched is:
t = 1.26 + 1.26 = 2.52 seconds
The time taken by the arrow to return to the ground is 2.52 seconds.
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