Question

an arrow is shoot at an angle of 40° to the horizontal with a velocity of 19.6 m/s. Find 1. maximum height 2.time of flight. 3. horizontal range

Answer 1

U=19.6m/s, angle c=40 (i) h max=((u*sin c) power 2)/2g Simply put the values  (ii) time of flight =(2u sin c) /g  again put the vaules (iii) range =(u power 2 sin 2c)/g Here multiply the angle c by 2 and then take the sin value of it