Question

An arrow is thrown in the air. Its time of flight is 5s and range is 200m.find vertical component of velocity
Horizontal component of velocity
Angle with vertical

Answer 1

Time of flight
T = 2uSinx / g
5 = 2uSinx / 10
uSinx = 25 m/s
Vertical component of velocity = uSinx = 25 m/s

Range
R = 2u^2 Sinx Cosx / g
200 = 2u^2 Sinx Cosx / 10
1000 = u^2 Sinx Cosx
1000 = (uSinx) × uCosx
1000 = 25 × uCosx
uCosx = 40 m/s
Horizontal component of velocity = uCosx = 40 m/s

Divide both the components of velocity
25 / 40 = Tanx
Tanx = 5/8
x = 32°
Angle with vertical = 90 - 32 = 58°

Answer 2

Explanation:

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