Math, asked by kurkure77, 9 months ago

An article passing through two hands is solid at a profit of 38% at the original cost price. If the dealer makes a profit of 20%, then the profit per cent made by the second is ?​ Any mod here please answer.​

Answers

Answered by Anonymous
1

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An article passing through two hands is solid at a profit of 38% at the original cost price. If the dealer makes a profit of 20%, then the profit per cent made by the second is ?

\small \blue {\sf{αnѕwєr :- }}

Let original price was Rs. 100.

With 38% profit the selling price would be

=100+38% of 100=100+

100

38

×100= Rs. 138

First dealer makes a profit of 20% , then he must have sold it at,

=100+20% of 100=100+

100

20

×100= Rs. 120

Now, profit for second dealer =138−120= Rs. 18

% profit =

100

18

×120=15 %.

Answered by Anonymous
1

Answer:

\huge\underline\bold {Answer:}

Let the initial cost price of the article be 100 rupees.

Profit = 20%

S.P. of the 1st dealer

 =  \frac{100 \times 120 }{100}  = 120 \: rupees

Let the second profit % = x. Then,

S.P. of the 2nd dealer

 =  \frac{120 \times (100 + x)}{100}

Final S.P. of the article after passing through two hands at a profit = 38%

 =  \frac{100 \times (100 + 38}{100}  = 138

Given,

 \frac{120 \times (100 + 38)}{100}  = 138

 =  > 12000 + 120x = 13800

 =  > 120x = 1800 \\  =  > x = 15\%

So, if the dealer makes a profit of 20%, then the profit per cent made by the second is 15%.

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