Question

An article was sold at a profit of 12%. If the cost price would be 10% less and selling price would be Rs.5.75 more, there would be a profit of 30%. Then at what price it should be sold to make a profit of 20% ?

Answer 1

cost price of articles=x
s.p different is 5.75

130/100*90/100*x-112/100=5.75
(117-112)/100*x=5.75
x=115
to sold for 20% profit
115*120/100=138

Answer 2

Answer:

The article must be sold at Rs. 138 to make a profit of 20%.

Step-by-step explanation:

Let the Cost Price be x.

Given: Profit % = 12%.

Profit $=\frac{12}{100} \times x=\frac{12 x}{100}$

∴ Selling Price = Cost Price + Profit $=x+\frac{12 x}{100}=\frac{100 x+12 x}{100}=\frac{112 x}{100}$

Given conditions are:

Cost Price would be 10% less.

∴ New Cost price $=x-\frac{10}{100} x=\frac{100 x-10 x}{100}=\frac{90 x}{100}=\frac{9 x}{10}$

And selling price would be Rs.5.75 more.

∴ New Selling Price$=\frac{112 x}{100}+5.75$

Then, Profit = 30% .

Hence, $\frac{130}{100} \times \frac{9}{10} x-\frac{112 x}{100}=5.75\begin{array}{l}{=>\frac{117}{100} x-\frac{112}{100} x=5.75} \\ {=>\frac{5}{100} x=5.75} \\ {=>x=\frac{5.75 \times 100}{5}=\frac{575}{5}} \\ {\Rightarrow>x=115}\end{array}$

Thus, Cost Price = RS 115.

Profit to make =20%

∴ Selling Price $\begin{array}{l}{=R s 115+\frac{20}{100} \times R s 115=R s 115+R s 23} \\ {=R s 138}\end{array}$

The article must be sold at Rs 138.