Physics, asked by BrainlyHelper, 1 year ago

An artificial diamond crystal has been manufactured by subjecting carbon in the
form of graphite to a pressure of 1.55 x 1010 Nm-2 at a high temperature. What must
have been the original volume of the diamond, whose mass before cutting was about
175g? Assuming that natural diamonds were formed at similar high pressure within the
earth, the density of the diamond = 3.5g cm-3 and its bulk modulus = 62 x 1010 Nm-2.

Answers

Answered by prashant120
4
A synthetic diamond (also known as an artificial diamond, cultured diamond, or cultivated diamond) is diamond produced in an artificial process, as opposed to natural diamonds, which are created by geologicalprocesses. Synthetic diamond is also widely known as HPHT diamond or CVD diamondafter the two common production methods (referring to the high-pressure high-temperature and chemical vapor depositioncrystal formation methods, respectively). While the term synthetic is associated by consumers with imitation products, artificial diamonds are made of the same material (pure carbon, crystallized in isotropic 3D form).[1] In the U.S., the Federal Trade Commission has indicated that the alternative terms laboratory-grown, laboratory-created, and [manufacturer-name]-created "would more clearly communicate the nature of the stone".

Numerous claims of diamond synthesis were documented between 1879 and 1928; most of those attempts were carefully analyzed but none were confirmed. In the 1940s, systematic research began in the United States, Sweden and the Soviet Union to grow diamonds using CVD and HPHT processes. The first reproducible synthesis was reported around 1953. Those two processes still dominate the production of synthetic diamond. A third method, known as detonation synthesis, entered the diamond market in the late 1990s. In this process, nanometer-sized diamond grains are created in a detonation of carbon-containing explosives. A fourth method, treating graphite with high-power ultrasound, has been demonstrated in the laboratory, but currently has no commercial application.

Answered by prmkulk1978
7

Given :
mass of diamond= 175g
Density=3.5g/cm3
Density= mass/Volume
Volume=mass/density
=175/3.5
=50cm3

If the original volume of diamond is V then
V=50+Δ V
Δ V=V-50
Bulk Modulus=B=PV/ΔV
B/P=62x10¹⁰/1.55x10¹⁰ =40V/V-50

V=40V-2000
39V=2000

V=51.28cm3---------------(i)

Δ V =PV/B
=1.55 x 10¹⁰ x50/62 x10¹⁰
=1.25cm3
V=50+1.25 =51.25cm3-----------(ii)

comparing equations i and ii
Difference is seen only in second decimal place Hence original volume of diamond=51.3 cm3
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