Question

An artificial satellite orbits ina circular path .the height of satellite from the surface of the earth is 36000km.such a satellite is called geo-stationary satellite when the satellite is exactly vertically upwards the ground station ,it sends a signal .how much time will the signal take to reach the ground station .the speed of signal is 3×10to the power 8 ms-1

Answer 1

Distance = 36000 km=36000000 m
Speed =3×10^8 ms^-1
time =?
$\frac{36000000}{3 \times 10 {}^{8} } \\ \frac{36000000}{300000000}$
0.12 s

Answer 2

Given:

An artificial satellite orbits in a circular path. The height of the satellite from the  surface of earth is 36,000 km.

The speed of signal is 3 x  108 m/s​

To find:

How  much time will the signal take to reach the ground station.

Solution:

From given, we have,

The distance between the satellite and the ground station is denoted as "S"

The formula is,

S = vt

where, v = speed of signal = 3 × 10⁸ m/s

t = time taken.

substituting the above values in the formula, we get,

36,000 km = 3 × 10⁸ m/s × t

36,000 km = 300000 km/s × t

36 = 300  × t

t = 36/300 = 0.12 s

Therefore, the time taken by the signal to reach the ground station is 0.12 s.