Question

An artificial satellite revolves around the earth with an orbital velocity of 5.92 m/s. calculate the height of the satellite from the Earth's surface. (Given radius:-6380 km,g:-9.8m/s)​

Answer 1

Here, h=1000 km=1000×10

3

m=10

6

m

r=R+h=6.38×10

6

+10

6

=7.38×10

6

m

Orbital speed,

v

0

=

R+h

GM

=

7.38×10

6

6.67×10

−11

×6×10

24

=7364m s

−1

Time period,

T=

v

0

2πr

=

7.364×10

3

2×(22/7)×(7.38×10

6

)

=6297s