Question

An astronaut drops a hammer from 2m above the surface of the moon. If the acceleration due to gravity on the moon is 1.62m.s, how long will it take for the hammer to fall to the moons surface

Answer 1

Answer:

t=1.6sec

Explanation:

GIVEN:-

• height from which it dropped is $<strong>2m</strong><strong> </strong>$
• Acceleration(due to gravity) is $<strong>1.62m</strong><strong>/</strong><strong>s</strong><strong>^</strong><strong>2</strong>$

NEED TO FIND:-

• Time taken by hammer to reach the moon surface.

SOLUTION:-

we know that,

$t = \sqrt{ \frac{2h}{g} }$

where,

• t=time
• h=height
• g=acceleration due to gravity

$t = \sqrt{ \frac{2 \times 2m}{1.62 {ms}^{ - 2} } }$

$t = \sqrt{ \frac{4m}{1.62 {ms}^{ - 2} } }$

$t = \frac{2}{1.2} s$

$t = 1.6sec$

HOPE THAT HELPS!!