Question

An astronaut is on the surface of a planet whose air resistance is negligible. To measure the acc due to gravity he throws a stone upwards. He observes that stone reaches to a max height of 10 m and reaches the surface 4 s after it was thrown. Find acc due to gravity

Answer 1

Answer:

5 m/s^2

Explanation:

T = 2u/g

4 = 2u/g

4g = 2u

u = 2g.....(1)

H = u^2/2g

10 = (2g)^2/2g.....From (1)

10 = 2g

g = 5 m/ s^2