an astronaut on a new planet finds that he can jump a maximum horizontal distance of 30m with his initial speed of 9m/s. what is the value of g on this planet?
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horizontal distance = 30
initial velocity = 9m/s
s= ut+1/2gt^2
horizontally value of g is 0
30 = 9t + 0
t = 3.3 sec
vertically distance = 0
s = ut + 1/2gt^2
0 = 0×t + 1/2 × g × 3.3^2
o = 1/2×g×10.89
o = 5.44g
g = 0.18 m/s
initial velocity = 9m/s
s= ut+1/2gt^2
horizontally value of g is 0
30 = 9t + 0
t = 3.3 sec
vertically distance = 0
s = ut + 1/2gt^2
0 = 0×t + 1/2 × g × 3.3^2
o = 1/2×g×10.89
o = 5.44g
g = 0.18 m/s
pranjalyadav16:
thank you
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