Question

An astronaut whose height on the earth is exactly 6 ft is lying
parallel to the axis of a spacecraft moving at 0.90 c relative to
the earth. What is his height as measured by an observer in the
same spacecraft? By an observer on the earth?​

Answer 1

Explanation:

hope it is the answer

Answer 2

Answer:

The formula we will be using is the STR formula for length contraction. It goes like this:

L = Lo * square root of (1-(v squared/c squared))

Where L is the astronaut’s height as seen by the observer on Earth and Lo is his height in an inercial system observed in that system, A.K.A. on Earth.

There is no need for transfering the height into the metric system, as we will be working with constants - the c’s in the equation will cancel each other out.

The resulting equation is simple :

6 * square root of (1- (0,9 squared))

that equals

6 * square root of 0,19

that equals roughly

2,615 feet.

So, when measured by an observer on Earth, the astronaut is roughly 2,615 feet tall.